Asked by Joris Lambrecht
on 9 Jun 2011

I want to be able to quickly determine the interval resulting from unions and intersections of various intervals. The number of intervals may vary, so the method needs to be somewhat flexible.

In regular Matlab I have only found a way to intersect sets (e.g. {1,2,3} u {2,4}) not intervals (e.g. [0.1 3.3) n (1.1 2.9])

where 'u' indicates union and 'n' indicates intersection.

Example: ([1.1, 2.3] u [2.8 3.2]) n ([1.9, 3.1] u [4.2 4.3]) n [1.7, 3.2] = [1.9,2.3] u [2.8, 3.1]

In MuPad, you can do the following: (Dom::Interval([1.1, 2.3]) union Dom::Interval(2.8, 3.2)) intersect (Dom::Interval([1.9, 3.1]) union Dom::Interval(4.2, 4.3)) intersect (Dom::Interval([1.7, 3.2]))

Any ideas on how to do this without MuPad? I've seen the 'interval merging' file exchange entry but it only handles unions of intervals.

Thanks!

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Answer by Sean de Wolski
on 9 Jun 2011

doc intersect doc union

and friends. Beware of floating points, however.

fpno = @(x)uint32(x*1000); %get rid of floating points fpyes = @(x)double(x)/1000; %bring 'em back fpyes(intersect(fpno([1.1 2.2]), fpno(1.2:.1:3.4)))

But I still don't understand how you're defining the interval as I can't get the same results as your example.

Joris Lambrecht
on 9 Jun 2011

intersect and union functions only operate on sets (not intervals). Like you say, beware floating points:

intersect([1.1 2.2], [1.2 3.4])

ans =

Empty matrix: 1-by-0

I want the result [1.2 2.2]

I can multiply my floating point numbers by a factor (determining precision, e.g. 1000 will result in 3 decimal place precsion), round them to make integers, construct sets from the integers, operate on these sets (using intersect and union), and then divide by my factor to get back to floating point. However this seems unnecessary and will generate large arrays to compare if I want high precision.

Sean de Wolski
on 9 Jun 2011

So what increment are you using to define an "interval"?

Answer by Walter Roberson
on 9 Jun 2011

Union and intersection of intervals can be done with min() and max() and appropriate logic; I remember implementing the logic about 6 years ago (probably in perl.) I did not, however, have to worry about open vs closed intervals: the representation and logic gets messier for those.

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