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I found strange error in matlab R2013a calculation using0 'floor'

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Use variable c1=0.011. c1 is multiplied by 10 until c1=11. Then use floor(c1) and get value 10
c1=0.011;
c1=c1*10;
c1=c1*10;
c1=c1*10;
floor (c1)
ans =
10
Then use variable c1=0.0011. c1 is multiplied by 10 until c1=11. Then use floor(c1) and get value 11
c1=0.0011;
c1=c1*10;
c1=c1*10;
c1=c1*10;
c1=c1*10;
floor (c1)
ans =
11
Then use variable c1=0.11. c1 is multipled by 10 until c1=11. Then use floor(c1) and get value 11
c1=0.11;
c1=c1*10;
c1=c1*10;
floor (c1)
ans =
11
WHY the first result differ from second and third?

Risposte (1)

A Jenkins
A Jenkins il 25 Ott 2013
Because floating point math is a strange thing.
Try setting
format long
and then rerun your above calculations. (Remove the semicolons so you can the results.)

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