How to create the definite cycle and to display the result of a cycle in a single matrix of a definite size?

Hello, I have cycle to represents b as matrix.

m=[];
  b=[4]; 
      for i=0:6 %Creating cycle 
          b=circshift(b,[0,i]); %Shift b 
          z=zeros(1,7,'int8'); %Create zeros string to represents b as 0 0 0...b..0
          if b==0 %If b=0 then z=1 0 0...0
              z(1)=1;
              m=[m; z];
          else
              z(b)=b; 
              b=mod(b,7); 
              b=b+1;
              m=[m; z];
          end
      end
ANSWER:
  m =

        0    0    0    4    0    0    0
        0    0    0    0    5    0    0
        0    0    0    0    0    6    0
        0    0    0    0    0    0    7
        1    0    0    0    0    0    0
        0    2    0    0    0    0    0
        0    0    3    0    0    0    0

I need to create the cycle for represent matrix b, for example, b=[1 2; 5 6] . In the form matrix m dimension 7*2x7*2=14x14. Only necessary that each value of b displayed by its matrix m For example, for b=[1 2; 3 4], I need create the following m:

m =

    1    0    0    0    0    0    0    0    2    0    0    0    0    0
    0    2    0    0    0    0    0    0    0    3    0    0    0    0
    0    0    3    0    0    0    0    0    0    0    4    0    0    0
    0    0    0    4    0    0    0    0    0    0    0    5    0    0
    0    0    0    0    5    0    0    0    0    0    0    0    6    0
    0    0    0    0    0    6    0    0    0    0    0    0    0    7
    0    0    0    0    0    0    7    1    0    0    0    0    0    0
    0    0    0    0    5    0    0    0    0    0    0    0    6    0
    0    0    0    0    0    6    0    0    0    0    0    0    0    7
    0    0    0    0    0    0    7    1    0    0    0    0    0    0
    1    0    0    0    0    0    0    0    2    0    0    0    0    0
    0    2    0    0    0    0    0    0    0    3    0    0    0    0
    0    0    3    0    0    0    0    0    0    0    4    0    0    0
    0    0    0    4    0    0    0    0    0    0    0    5    0    0

Help me, please!

Answer 1

[Amit]

A = eye(7).*repmat(1:7,7,1);
[x,y] = size(b);
m = zeros(7*x,7*y);
for i = 1:x
  for j = 1:y
    if (b(i,j) == 0)
       m((i-1)*7+1:i*7,(j-1)*7+1:j*7) = 0;
    else
       m((i-1)*7+1:i*7,(j-1)*7+1:j*7) = circshift(A,(-1)*b(i,j)+1);
    end
  end
end

This will do it.

[Meffix]

Ooh!

Thank you very much!!!!

Answer 2

[Amit]

Here is a simpler way to do this:

A = eye(7).*repmat(1:7,7,1);
[x,y] = size(b);
m = zeros(7*x,7*y);
for i = 1:x
  for j = 1:y
     m((i-1)*7+1:i*7,(j-1)*7+1:j*7) = circshift(A,(-1)*b(i,j)+1);
  end
end

[Amit]

btw, the solution you've shown is for [1 2;5 6] and not for [1 2;3 4]

[Meffix]

yes, last m shown for b=[1 2; 5 6]

It's right!

But I need for 0 elements of b represent as zero matrix

[Amit]

A = eye(7).*repmat(1:7,7,1);
[x,y] = size(b);
m = zeros(7*x,7*y);
for i = 1:x
  for j = 1:y
     m((i-1)*7+1:i*7,(j-1)*7+1:j*7) = circshift(A,(-1)*b(i,j));
  end
end

if this is not what you want, please post an example with atleast 1 element of b being 0.

[Meffix]

for example b=[0 2; 5 6]

m =
    0    0    0    0    0    0    0    0    2    0    0    0    0    0
    0    0    0    0    0    0    0    0    0    3    0    0    0    0
    0    0    0    0    0    0    0    0    0    0    4    0    0    0
    0    0    0    0    0    0    0    0    0    0    0    5    0    0
    0    0    0    0    0    0    0    0    0    0    0    0    6    0
    0    0    0    0    0    0    0    0    0    0    0    0    0    7
    0    0    0    0    0    0    0    1    0    0    0    0    0    0
    0    0    0    0    5    0    0    0    0    0    0    0    6    0
    0    0    0    0    0    6    0    0    0    0    0    0    0    7
    0    0    0    0    0    0    7    1    0    0    0    0    0    0
    1    0    0    0    0    0    0    0    2    0    0    0    0    0
    0    2    0    0    0    0    0    0    0    3    0    0    0    0
    0    0    3    0    0    0    0    0    0    0    4    0    0    0
    0    0    0    4    0    0    0    0    0    0    0    5    0    0