HOW TO READ SPECIAL CHARACTERS IN A SINGLE ARRAY

a1=('a':'z');

b1=('A':'Z');

c1=('0':'9')

IN the above commands a1 contains a to z, and b1 contains A to Z, *c1 contains 0 to 9.

in the similar way how to read special characters like , . ! @ # $ % ^ & * ( ) _ in a single array

Answer 1

[Benjamin Avants]

If you look up the ascii values of the characters you're looking for, you can make an array of those values and then cast it to char

Example:

d1 = 1:33;
d1 = char(d1);

[Walter Roberson]

Note though that the initialization gets long and tedious if you want the printable characters available in UNICODE up to code point 65535

[sonam s]

d1 = 1:33;

d1 = char(d1);

*tTHANK YOU .BUT THE CODE IS NOT WORKING .IT IS DISPLAYING 33 SQUARE BOXES .PLEASE HELP *

[Benjamin Avants]

1:33 was just an example. You'll need to look up the actual ascii character values online. I would suggest a google search for "ascii table". I think most of the characters in the 1:33 range are special characters, not symbols. Try the range 33:47 for a few of the printable characters.

Answer 2

[Walter Roberson]

 char([33:47, 58:64, 91:96, 123:126])

after that one gets into the non-ASCII characters such as '©'.

Another way of expressing this is:

d1 = union(union(a1, b1), c1);
d2 = setdiff(' '+1:127, d1);

Note: earlier I had setintersect() instead of setdiff()