How to find the indices of element occuring once in a vector?
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Hello all
I want to know...How can I get the indices of a value that is occuring only once in a vector...please guide.
Example: A=[1 1 0 -1 0 0 1 0 1 1]
Task: To identify the indices of -1 (as it is occuring only once) in A.
Please Help!!!
Regards
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Cedric
il 23 Mag 2014
Modificato: Cedric
il 23 Mag 2014
There are ways to solve your problem based on HISTC or ACCUMARRAY. However, the simplest approach if you really have only two situations (unique 1 or unique -1) is probably the following:
if sum( A == 1 ) == 1
pos = find( A == 1 ) ;
else
pos = find( A == -1 ) ;
end
value = A(pos) ;
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Più risposte (3)
George Papazafeiropoulos
il 23 Mag 2014
Modificato: George Papazafeiropoulos
il 23 Mag 2014
A=[1 1 0 -1 0 0 1 0 1 1];
[~,c]=histc(A,unique(A));
out=A(c==1);
2 Commenti
Cedric
il 23 Mag 2014
Sagar, you should take the time to understand his example. In particular, see what c is, what c==1 is, etc. Maybe read about logical indexing, and if you cannot use the latter and really need the position of unique element(s), read about FIND.
Mahdi
il 23 Mag 2014
If you're looking specifically for the value of -1, you can use the following:
index1=find(A==-1)
3 Commenti
George Papazafeiropoulos
il 23 Mag 2014
Modificato: George Papazafeiropoulos
il 23 Mag 2014
A=[1 1 -1 0 0 0 1 0 1 1];
[~,c]=histc(A,unique(A));
out=find(c==1);
3 Commenti
George Papazafeiropoulos
il 23 Mag 2014
Try the above code for different A. Define A as you want and then execute the two last lines of the code. I think it works...
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