How can I find the largest number

Hi, I have 3 numbers and I have to find the biggest one, what is the best way? This is the code:

T=200
if isempty(counter) || counter >= T
    counter=0;
d1=0.1
d2=0.2
d3=0.6
else counter=counter+1
if counter>0
if d1=max([d1,d2,d3)]
...
elseif d2=max([d1,d2,d3)]
...
elseif d3=max([d1,d2,d3)]
...
end
end
end

But this code doesn't work, thank you

[Mischa Kim]

Do you only need the number (0.6) or do you want to know the specific variable ( d3 )?

[alessandro]

I just need to know which is the greater one in order to define another variable, for example:

    if d1=max([d1,d2,d3)]
    V=V1
    elseif d2=max([d1,d2,d3)]
    V=V1
    elseif
    ...

[Roberto Calandra]

Remember that with d1=max([d1,d2,d3]) you are assigning a variable to d1but what you want is checking for equality as in d1==max([d1,d2,d3])

Answer 1

[Elias Gule]

numbers = [num1 num2 num3]; % the array of numbers from which to search 
maxVal  = max(numbers);     % the highest number

Answer 2

[Roberto Calandra]

Something like this?

 switch max([d1,d2,d3])
 case {d1}
      V=V1
 case {d2}
      V=V2
 case {d3}
      V=V3
 end

Answer 3

[Robert Cumming]

you need to use

 ==

for comparison, i.e.

 if d1==max([d1,d2,d3)]

etc...

Answer 4

[b.lokendra sri sai]

T=200

if isempty(counter) || counter >= T

counter=0;

d1=0.1

d2=0.2

d3=0.6

else counter=counter+1

if counter>0

if d1=max([d1,d2,d3)]

...

elseif d2=max([d1,d2,d3)]

...

elseif d3=max([d1,d2,d3)]

...

end

end

end