FFT (fast fourier transform) matlab default example (need explanation)

I try to figure out how the FFT command works on matlab and I came across this example that matlab central gives out at this link http://www.mathworks.com/help/matlab/ref/fft.html

Can somebody explain to me how this code works?? If not all the code than this part of it

NFFT = 2^nextpow2(L); % Next power of 2 from length of y
Y = fft(y,NFFT)/L;
f = Fs/2*linspace(0,1,NFFT/2+1); %why 2+1 ????

[Yona]

NFFT/2+1
is equal to

(NFFT/2)+1
in 0:10 you have 11 point because you have the start and stop too. so you need to add another point.

[John Bitzios]

Thanks for the reply Yona! Can you explain the whole thing from top to bottom so I can get the whole picture?? That would help me a lot :)

Answer 1

[Andy L]

L is the length of your signal. It is used to determine the time vector t and so on. nextpow2 is used to pad the signal passed to fft - this speeds up it's computation compared to a signal not of that length. Your question RE line 3 was already answered.

[John Bitzios]

Thanks a lot!

[Andy L]

No worries