Attempted to access y(15); index must be a positive integer or logical.
12 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
Here is my code:
clear;
for t=0:0.01:4;
i=t*100+1;
if t<2
y(i)=3.5*exp(-t/2)*cos(2*pi*t);
T(i)=t;
else
y(i)=3.5*exp(-1)*cos(6*pi*t);
T(i)=t;
end
plot(T, y,'g','linewidth',2)
end
As you can see, I want to plot the piecewise function. To store y and t as vectors, I created an index i . But when i equals 15, it reports 'Attempted to access y(15); index must be a positive integer or logical.' But when t=0.14, i=15 and it makes sense, I think.So how can it be wrong? Please help me with the problem. Thanks!
0 Commenti
Risposta accettata
Roger Stafford
il 4 Set 2014
Modificato: Roger Stafford
il 4 Set 2014
If you do a high accuracy check on what you think is an i-value of 15, you will find that it is off from the exact integer 15 by 1 bit or so at its least significant end. That is caused by the fact that since your computer is using binary numbers, it cannot represent 0.01 exactly, and multiplying this number by an integral multiple of 100, which you are doing, does not always yield an integer. Welcome to the world of binary numbers!
Instead of your "for t=0:0.01:4; i = t*100+1;" you should write:
for i = 1:401
t = (i-1)/100; % <-- or else t = linspace(0,4,401) or t = 0:0.01:4
etc.
0 Commenti
Più risposte (1)
Iain
il 4 Set 2014
Its a floating point error down at the 15th significant figure. If you simply round "i", it'll work.
Vedere anche
Categorie
Scopri di più su Logical in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!