double error syms code

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yogeshwari patel
yogeshwari patel il 4 Gen 2022
syms x t a
%a=1/2;
N=3;
U=zeros(1,2,'sym');
A=zeros(1,2,'sym');
B=zeros(1,2,'sym');
series(x,t)=sym(zeros(1,1));
U(1)=simplify(1+sin(x));
%alpha=input('enter the value of alpha=')
%case1
% for i=1:8
% U(i+1)=simplify((diff(U(i),x,2)+U(i))*gamma(a*(i-1)+1)/gamma((a*(i+1-1))+1));
% end
for i=1:3
A=0;
for j=1:i
A=A+U(j)*U(i-j+1);
end
U(i+1)=simplify((diff(U(i),x,2)-A(1))
end
disp(U)
for k=1:2
series(x,t)=simplify(series(x,t)+U(k)*(power(t,a*(k-1))));
end
series
% C=zeros(1,1);
% series
C=zeros(1,1);
for x=1:3
e=(x-1)/10;
for t=1:6
f=((t-1)/10);
C(x,t)=series(e,f);
end
end
The following error occurred converting from sym to double:
Unable to convert expression into double array.
Error in fractionakelingordanequation (line 33)
C(x,t)=series(e,f);
  1 Commento
Mitchell Thurston
Mitchell Thurston il 4 Gen 2022
it looks like this particular function is undefined at (0,0), so you might have some issues with that loop

Accedi per commentare.

Risposta accettata

Steven Lord
Steven Lord il 4 Gen 2022
Preallocate C to be a sym array.
syms x
C=zeros(3, 6, 'sym')
C = 
C(2, 3) = x.^2
C = 

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