Average number of y for y=f(x) where there are several y values for the same x

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I have an array y where y is a function of x but for every x there are multiple values of y.
x=[x1 x1 x1 x1 x1 x2 x2 x2 x2 x3 x3 x3 x3 x3 ...]
y=[y1 y2 y3 y4 y5 y6 ... yn]
How can I separate the values of y related to each unique x and e.g. calculate their average (or maximum or minimum) to have an array of unique x and y elements at the end that would look like this:
x=[x1 x2 x3 ... xn]
y=[mean(y1:y5) mean(y6:y9) mean(y10:y14)...]

Accepted Answer

Voss
Voss on 4 Feb 2022
% creating some x and y to replicate your situation, as I understand it:
x = repelem([1 2 3 4],1,5);
y = randn(size(x))+repelem(2:2:8,1,5);
disp(x); disp(y);
1 1 1 1 1 2 2 2 2 2 3 3 3 3 3 4 4 4 4 4 2.0493 1.9038 2.2196 0.8905 1.6911 5.0208 3.4631 5.1964 3.8335 4.7127 5.7153 5.3221 7.5308 5.2093 4.9359 9.5675 8.4060 7.6161 7.4658 8.1718
% Perform the requested task, as I understand it:
[ux,~,jj] = unique(x);
nux = numel(ux);
uy = zeros(1,nux);
for ii = 1:nux
uy(ii) = mean(y(jj == ii));
end
disp(ux); disp(uy);
1 2 3 4 1.7509 4.4453 5.7427 8.2455

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