How to split a column with numerical values?

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Hi all,
I have a 1x72 structure with one column containing three numerical values (attched).
I would like to convert it into a 3x72 table with each numerical value in a seperate column with diffrent name, for example:
'name 1' 'name 2' 'name 3'
0.9377 0.9246 0.9982
Can you help please?

Accepted Answer

Stephen23
Stephen23 on 2 Mar 2022
Edited: Stephen23 on 2 Mar 2022
Here are two robust MATLAB approaches (both much more robust than blindly using STRUCT2ARRAY):
S = load('data.mat');
ICCs = S.ICCs
ICCs = 1×72 struct array with fields:
Metrics
T = array2table(vertcat(ICCs.Metrics),'VariableNames',{'XX','YY','ZZ'})
T = 72×3 table
XX YY ZZ _______ _______ _______ 0.93769 0.92456 0.99817 0.86066 0.90427 0.99263 0.84509 0.85719 0.98951 0.8738 0.89004 0.99273 0.55918 0.68187 0.55212 0.7432 0.56476 0.70838 0.67489 0.51727 0.64014 0.764 0.72324 0.6591 0.81925 0.90581 0.90397 0.71105 0.74472 0.83758 0.71823 0.71584 0.84393 0.90053 0.85199 0.96139 0.90284 0.82024 0.98977 0.78653 0.76117 0.97559 0.75978 0.70471 0.97234 0.78341 0.70018 0.97691
T = splitvars(struct2table(ICCs),'Metrics','NewVariableNames',{'XX','YY','ZZ'})
T = 72×3 table
XX YY ZZ _______ _______ _______ 0.93769 0.92456 0.99817 0.86066 0.90427 0.99263 0.84509 0.85719 0.98951 0.8738 0.89004 0.99273 0.55918 0.68187 0.55212 0.7432 0.56476 0.70838 0.67489 0.51727 0.64014 0.764 0.72324 0.6591 0.81925 0.90581 0.90397 0.71105 0.74472 0.83758 0.71823 0.71584 0.84393 0.90053 0.85199 0.96139 0.90284 0.82024 0.98977 0.78653 0.76117 0.97559 0.75978 0.70471 0.97234 0.78341 0.70018 0.97691

More Answers (2)

KSSV
KSSV on 2 Mar 2022
Edited: KSSV on 2 Mar 2022
load('data.mat')
name = reshape(struct2array(ICCs),3,[])' ;
T = array2table(name);
Or you can use
load('data.mat')
T = struct2table(ICCs);
  1 Comment
Stephen23
Stephen23 on 2 Mar 2022
Edited: Stephen23 on 2 Mar 2022
Avoid this code, it is not robust. Consider what would happen if the structure contains other fields.
One of the main benefits of using structures is that each field can be processed independently. This approach using STRUCT2ARRAY discards that benefit, making the code more fragile to future data changes.
EDIT: after KSSV editted and added a second approach: the second code suggestion does not work because the OP requested three columns in the table, and that code only returns one.
Sigh.

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Mathieu NOE
Mathieu NOE on 2 Mar 2022
hello
this would be my suggestion
load data.mat
% convert structure to numerical array
a = struct2cell(ICCs);
a = squeeze(a);
a = vertcat(a{:});
% create table
t = array2table(a,'VariableNames',{'name 1' 'name 2' 'name 3'});
  1 Comment
Stephen23
Stephen23 on 2 Mar 2022
One of the main benefits of using structures is that each field can be processed independently. This approach using STRUCT2CELL discards that benefit, making the code more fragile to future data changes.
SQUEEZE (which is an abomination anyway) is not required if the variable is used for a comma-separated list.

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