How can I generate n*(n^2) matrix with n 1's per row, indented n times?

Hi,

I'm trying to generate the following matrix (n=3 in this case)

A1partition =

1 1 1 0 0 0 0 0 0

0 0 0 1 1 1 0 0 0

0 0 0 0 0 0 1 1 1

or for example if n=4:

A1partition =

1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0

0 0 0 0 1 1 1 1 0 0 0 0 0 0 0 0

0 0 0 0 0 0 0 0 1 1 1 1 0 0 0 0

0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1

But I'm struggling to indent the 1's each row. This is my code as now

n=3;
A = zeros(n,n*n);
for i = 1:n
    for j=1:n
        A(i,j)=1;
    end
end
A

which gives

A =

1 1 1 0 0 0 0 0 0

1 1 1 0 0 0 0 0 0

1 1 1 0 0 0 0 0 0

Answer 1

[KSSV]

n = 4 ; 
A = zeros(n,n,n) ;
for i = 1:n
    A(i,:,i) = ones(n,1) ;
end

A = reshape(permute(A,[1,2,3]),size(A,2),[])

A = 4×16

1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1

[Ingrid Wilson]

Thank you!