# How to repeat the matrix to complete the shape of Matrix

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Stephen john on 11 Apr 2022
Commented: Walter Roberson on 11 Apr 2022
Hello everyone i hope you are doing well.
I have the following Dataset,
one has shape of 1x586 and other has shape 1x48.
I want to repeat this matrix to to complete the shape of 1x1000 and 1x10000.
How can i do this in MATLAB
##### 1 CommentShowHide None
Rik on 11 Apr 2022
What have you tried so far?
Also, 48 and 586 are not integer fractions of 1e3 and 1e4. How do you want to deal with that?

Walter Roberson on 11 Apr 2022
Your requirements are not clear.
targetsize586 = 10000;
n586 = numel(Mat_586);
nrep = targetsize586 / n586;
fullrep = floor(nrep);
leftover = targetsize - fullrep * n586;
variation1 = [repmat(Mat_586, 1, fullrep), Mat_586(1:leftover)];
variation2 = repelem(Mat_586, 1, ceil(nrep)); variation2(targersize586+1:end) = [];
variation1 makes repeated copies of the matrix, like [1 2 3, 1 2 3, 1 2 3, 1 2 3, ...] as many times as possible to fit within the target size, and then makes a partial copy as large as needed to fit.
variation2 makes repeated copies of the elements, like [1 1 1 1, 2 2 2 2, 3 3 3 3, ...] with each element repeated as many times as needed until the overall would meet or exceed the target size, and then trims off enough copies of the last element to make the overall fit. So you might, for example, get 21 copies in a row of each value except the last, followed by (say) 18 copies of the last element.
Walter Roberson on 11 Apr 2022
targetsize = 10000;
output = [];
temp = reshape(YourData, 1, []); %ensure row
nt = numel(temp);
while nt >= targetsize
output = [output; temp(1:targetsize)];
temp = temp(targetsize+1:end);
nt = numel(temp);
end
nrep = ceil(targetsize / nt); %we know nt < targetsize at this point
temp = repmat(temp, 1, nrep);
output = [output; temp(1:targetsize)];

R2021b

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