- Add a "Delay" block to your model, and set its delay time to a few milliseconds (e.g. 5ms).
- Connect the output of your button to the input of the Delay block.
- Connect the output of the Delay block to your save condition block.
- When the button is pressed, it will send a signal to the Delay block, which will delay the signal by a few milliseconds before passing it to the save condition block. This will ensure that only one signal is sent, even if the button bounces multiple times.
Button Latency Problem Help
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I am working with Raspberry Pi on Simulink. I have a save condition includes push button. If I press the button, values will save to the worksace, but everytime I pressed that button, it takes too much time to turn off and this cause to save to much value. This button must be on/off real quick and needs to save only one value. How can I solve this?
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Vidip Jain
il 21 Feb 2023
In this situation, multiple signals are sent when the button is pressed. There are a few different ways to ensure that only one signal is sent when the button is pressed, but one simple method is to add a short delay after that button is pressed before reading its value. This delay can be implemented in software using a timer or delay loop.
Here's a simple example of how you could implement debouncing in your Simulink model:
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