# how to plot contour ?

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MS il 16 Dic 2022
Modificato: MS il 19 Dic 2022
How to do the below mentioned process in the loop and save contour. Please share your knowledge. Attached data for your reference.
I tried to create a loop but got the Error: Invalid array indexing. T = readtable('HB2B_2530.csv','PreserveVariableNames',true); Vx = table2array(T(:,:));%X TTT = Vx(:,10:13); A=unique(TTT,'rows'); Acell=splitapply(@(x){x}, A,findgroups(A(:,2))); Acell{:}; y1 = [Acell{1,:}];%first plane values y2 = [Acell{2,:}];%second plane values y3 = [Acell{3,:}];%third plane values y4 = [Acell{4,:}];%fourth plane values for i= 1:4 rg(i) = linspace(min(y(i)(:,1)), max(y(i)(:,1)), 100); cg(i) = linspace(min(y(i)(:,3)), max(y(i)(:,3)), 100); [Rg(i), Cg(i)] = meshgrid(rg(i), cg(i)); Zg(i) = griddata(y(i)(:,1), y(i)(:,3), y(i)(:,4), Rg(i), Cg(i)); contourf(Rg(i),Cg(i),Zg(i)); end
##### 2 CommentiMostra 1 commento meno recenteNascondi 1 commento meno recente
MS il 16 Dic 2022
No reason. I am unable to run in the loop

Accedi per commentare.

### Risposta accettata

Walter Roberson il 16 Dic 2022
Vx = table2array(T(:,:));%X
TTT = Vx(:,10:13);
A = unique(TTT,'rows');
Acell = splitapply(@(x){x}, A,findgroups(A(:,2)));
Acell{:};
y1 = [Acell{1,:}];%first plane values
y2 = [Acell{2,:}];%second plane values
y3 = [Acell{3,:}];%third plane values
y4 = [Acell{4,:}];%fourth plane values
y = {y1, y2, y3, y4};
N = length(y);
rg = cell(N,1); cg = cell(N,1);
Rg = cell(N,1); Cg = cell(N,1);
Zg = cell(N,1);
for i= 1:N
rg{i} = linspace(min(y{i}(:,1)), max(y{i}(:,1)), 100);
cg{i} = linspace(min(y{i}(:,3)), max(y{i}(:,3)), 100);
[Rg{i}, Cg{i}] = meshgrid(rg{i}, cg{i});
Zg{i} = griddata(y{i}(:,1), y{i}(:,3), y{i}(:,4), Rg{i}, Cg{i});
subplot(N,1,i);
contourf(Rg{i}, Cg{i}, Zg{i});
end
Acell will be a cell array in which each matrix is a composed of rows extracted from the array A that has four columns. It will have as many entries as there are distinct groups in the data. The code assumes that there are at least 4 such groups. Acell will have as many columns as findgrous(A(:,2)) has, which would be 1, so Acell will be som
So Acell{1,:} would be the same as Acell{1,1} since Acell will be something x 1. Since there is only one cell being accessed, the result of [Acell{1,1}] would be the same as if you had used Acell{1} directly .
Now suppose that somehow you had Acell being an N x 2 cell array such that Acell{1,:} would be different than Acell{1} . In such a case [Acell{1,:}] would be [Acell{1,1}, Acell{1,2}] which would be expecting to be able to horizontally concatenate those two arrays. But do we know if those (hypothetical) arrays are even the same height to be able to [] them together ? If these hypothetical arrays are, hypothetically, the same height then the result of the [] would have more than 4 columns, but your code processing y ignores anything past the 4th column... so why bother to [] the (hypothetical) rows together?
##### 7 CommentiMostra 6 commenti meno recentiNascondi 6 commenti meno recenti
MS il 19 Dic 2022
Modificato: MS il 19 Dic 2022
Thanks @Walter Roberson. i am discussing about the whole image is not saving automatically. I am attaching a full image wiht color label naming. Color label name is mssing while saving it automatically. Accedi per commentare.

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