Code for frequency of a number of bins

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Tam on 5 Feb 2023
Commented: Walter Roberson on 6 Feb 2023
I need to store into a variable the number of years (frequency) in which a certain number of incidents occured.
The code of the histogram plotted is below. Bin_centres is max/min values of freq(:,2), freq is the array. Column 1 are the years and column 2 are # of incidents.
I think I have to use hist.values and hist.BinEdges, but I don't know how to make that into a working code. I keep getting errors.
hist = histogram (freq(:,2), bin_centres)
Walter Roberson
Walter Roberson on 6 Feb 2023
"Bin_centres is max/min values of freq(:,2),"
freq(:, 2) is a vector. It has a single max and a single min. So you only have 1+1=2 bin boundaries. histogram puts data exactly equal to the last value into the previous bin so N edges results in (N-1) bins. 2 edges therefore creates exactly one bin. The result would be to count all of the values between the min and max, inclusive, which of course would just be the same as counting the non-nan inputs.

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Answers (1)

Sulaymon Eshkabilov
Sulaymon Eshkabilov on 6 Feb 2023
This is how you can plot hist() or histogram(), e.g.:
D = round(100*(randn(1000, 1)),0)+375;
hist(D, max(D))
histogram(D, min(D))
histfit(D, max(D))
  1 Comment
Tam on 6 Feb 2023
Thank you, but I just need a variable that stores the frequency of each bin. I've already plotted the graph. I don't know if I explained it properly.

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