xcorr vs conv: in latest MATLAB version

Hello, I get xcorr(x,y)=conv(x,fliplr(y)) when using the latest MATLAB edition. Has the defintion of xcorr(x,y) changed to xcorr(l)=summation(x(n),y(n-l)) in the latest version? I understand that in the older version, it used to be xcorr(l)=summation(x(n),y(n+l)) Kindly clarify. Thanks very much

1 Commento

hudieliu
hudieliu il 29 Set 2017
Modificato: hudieliu il 29 Set 2017
If length(x)==length(y),then xcorr(x,y)=conv(x,fliplr(y)) ,and length(xcorr(x,y))= length(x)*2-1. But if length(x)~=length(y), then they are not equal, and length(xcorr(x,y)) = 2*max(length(x),length(y))-1 while length(conv(x,y)) = length(x)+length(y)-1

Accedi per commentare.

 Risposta accettata

David Young
David Young il 27 Feb 2011

0 voti

Surely the definition of xcorr was, and still is, the final formula you give (with the + sign in the index), and this is consistent with xcorr(x,y) = conv(x, fliplr(y)) because convolution is defined by the formula with the - sign in the index.
Correlation and convolution are both operations with standard definitions generally accepted by mathematicians. I don't have the Signal Processing Toolbox, but I can't imagine that MATLAB would ever have implemented anything other than the standard operations.

Più risposte (1)

Andreas Goser
Andreas Goser il 27 Feb 2011

0 voti

I could not find a change documented in the release notes - compatibility considerations. I assume that you ask this question not out of curiosity, but have different results in different releases? In this case, please post this as a new question with example data and information about releases and platforms you use.

1 Commento

Andreas,
Thank you very much for the response. I am using this for a project and am not able to find any difference between xcorr and conv(fliplr). However, the info regarding older version was mentioned by a user who had used prior edition of MATLAB - where he was seeing the difference between the two in terms of sign of the lagindex (mentioned in my earlier question). If I can get access to the prior edition (which carried a different definition of the xcorr), I will post both the results.
Thanks again

Accedi per commentare.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by