Is there any expert who knows how the SNR result in the RF Budget Analyzer is calculated? Why is it inconsistent with the value I calculated?

6 visualizzazioni (ultimi 30 giorni)
The way I calculated is:SNR=0-lg(KTB)=0-10lg(1.38*10^-23*290*100*10^6)=123.9772
There is a difference of 30 dB from the simulation result. Which part is wrong?

Risposta accettata

David Goodmanson
David Goodmanson il 15 Apr 2025
Modificato: David Goodmanson il 15 Apr 2025
Hi ZW,
It's good to work out things independently as you are doing. The available power is 0 dBm, i.e. 1 milliwatt = -30 dB watts. So now you have
-30 -10*log10(1.38*10^-23*290*100*10^6)
which basically matches the result.
(Using more decimal places for the Boltzmann constant, k = 1.38065e-23, matches the result to all four decimal places).
  2 Commenti
志刚
志刚 il 16 Apr 2025
It was really an enlightenment to me. Moreover, you carefully pointed out the issue of the accuracy of the value of the Boltzmann constant. Thank you DG so much!
志刚
志刚 il 16 Apr 2025
Modificato: 志刚 il 16 Apr 2025
Do you know the reasons for the following two questions? As shown in the figure,
First, why the SNR remains unchanged after cascading?
Second, the OIP3 value after cascading is also different from the result I calculated.
The calculation methods I used for the cascaded SNR and the cascaded OIP3 are as follows.

Accedi per commentare.

Più risposte (0)

Categorie

Scopri di più su RF Blockset Models for Transceivers in Help Center e File Exchange

Prodotti


Release

R2023a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by