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Questa domanda è chiusa. Riaprila per modificarla o per rispondere.
Hlep change the program .As easy and automatic.
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i=1;
while (100-2^i>0)
i=i+1;
end
k=i-1
e1=100-2^k
while (e1-2^k<0)
k=k-1;
end
k1=k
e2=e1-2^k1
while(e2-2^k1<0)
k1=k1-1;
end
k2=k1
e3=e2-2^k2
1 Commento
the cyclist
il 16 Lug 2015
Please explain the problem with the code. Are you getting an error? Are you getting an unexpected result? Does this code run too slowly for your purpose?
You need to help explain all this to us, if you want us to help you.
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Questa domanda è chiusa.
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