I will appreciate any suggestion on this simple code. I want to substitute the elements of x >5 with 6 and x<5 with zero.

 for j=1:1:8
x=[1 2 3 4 5 6 7 8];
if x(j)>5
x(j)=subs(x(j),x(j),6);
else
x(j)=subs(x(j),x(j),0);
end
end

Answer 1

[Azzi Abdelmalek]

idx=x>5
x(idx)=6
x(~idx)=0

[Isaac]

Please, could you be more explicit with your answer.

[Isaac]

Okay, thanks. I got it now.

[Isaac]

In the event when I have two conditions to satisfy, please assist:

for j=1:1:8 x=[1 2 3 4 5 6 7 8]; y(j)=x(j).^2; idx=(x>pi&&x<7); idy=y<2; y(idy)=0; y(idx)=90; end

[Steven Lord]

Don't define x inside your loop. It's unnecessary and is just going to waste time.

Don't use a loop; vectorize your code as Azzi suggested.

&& is intended to short-circuit when the two criteria you're trying to AND together evaluate to a scalar value. In this case, your criteria do not evaluate to scalar values. In that case, use & to perform elementwise AND.

Answer 2

[matico]

Also:

 x=[1 2 3 4 5 6 7 8];

 x(x>5) = 6;
 x(x<=5) = 0;