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Question about assigning prhs to an int * in a mex file.

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Pei JIA on 22 Jan 2011
Another silly question on mexFunction.
I tried the following code:
void mexFunction(int nlhs, mxArray *plhs[], int nrhs, const mxArray *prhs[])
int *data = mxGetPr(prhs[0]);
mexPrintf("%f \n", data[0]);
If data is defined as
double* data = mxGetPr(prhs[0]);
what's printed out is correct.
If data is defined as the above
int* data = mxGetPr(prhs[0]);
what's printed out is always 0.000000, no matter what have been stored in "prhs".
Does that mean, for mexFunction, the unique way to cope with data is
double *data = mxGetPr(prhs[0]);
and I have to re-assign the data in different format by myself?

Answers (2)

Bård Skaflestad
Bård Skaflestad on 22 Jan 2011
The mxGetPr() function always returns a pointer to double. Pointers to double are distinct from pointers to int and there exists no direct conversion between the two. Furthermore, the mxGetPr() function is only really applicable if the mxArray* satisfies either of mxIsDouble() or mxIsComplex(). If the mxArray* is any other data type (e.g., if mxIsInt32() returns true), then you must use the mxGetData() function to get at the actual data members of the mxArray*.
The solution to your problem depends a lot on the expected input to your mexFunction(). If you want to accept (arrays of) any MATLAB (numeric) data type (e.g., double or uint32), then you will typically have to allocate some memory for your int *data in your mexFunction() (see mxMalloc() or mxCreateNumericMatrix()) and then loop over the data members of the mxArray* to manually effect the type conversion.
Jan on 25 Jan 2011
Dear Walter, thanks for the important information. As far as I can see, I did *not* mix "int" and "int32_T", because these terms appear in different sentences.
You are right: The ISO C++ standard says clearly that the typecasting between different pointer types depend on the compiler. E.g. the alignment can cause problems when casting char* to a long*.
On the other hand, do you know a compiler supported by Matlab, which replies different values for "(int *) mxGetPi" and "(int *) mxGetImagData"?
However, it seems like the OP has another problem: Either he tries to cast the value by casting the pointer type, or he calls he uses the "%f" format for an int value (or *she*).

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Siddharth Shankar
Siddharth Shankar on 26 Jan 2011
int *data = (int *) mxGetData(prhs[0]);
is what you need to do. mxGetData will return a void ptr which then needs to be "cast" appropriately.
Bård Skaflestad
Bård Skaflestad on 28 Jan 2011
Actually, if you're in C (*not* C++), then the output of |mxGetData()| (i.e., a |void*|) can be directly converted to a pointer to |int|. This is what Walter Roberson mentioned earlier. In other words, in the C programming language, explicitly converting a |void*| into an |int*| by means of a cast is not required and becomes purely a matter of personal style.
I prefer not to add the explicit cast myself.

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