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I have a "x1c" cell, and with the following code:

tn=1

for N=1:6591

for t=1:200

k=(((abs(x1c{t,1}(N)-x1c{1,1}(N))).^2))/(6591*200*6)

tn=tn+1;

end

end

I would like to take the "limit of the "k" while t goes infinity"; is it possible?

Image Analyst
on 27 Feb 2016

Image Analyst
on 28 Feb 2016

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