How to spread out an arry of matrix randomly

1 visualizzazione (ultimi 30 giorni)
I have random matrix like this
[2 2 2 2 1 1 1 1 1 -1 -1 -1 -1 -1]
and depend to the result of calculation number of 2 1 -1 will be different but i want to spread these numbers randomly like this e.g. [2 1 2 -1 1 1 2 -1 2 -1 -1 2 ]
how should i do this?

Risposte (2)

Walter Roberson
Walter Roberson il 18 Mag 2016
YourVector(randperm(length(YourVector)))
  2 Commenti
Hamid Reza Barzegar
Hamid Reza Barzegar il 18 Mag 2016
first=100;
Second=50;
Third=50;
Alloc_Sc=[2*ones(1,first),ones(1,Second),-1*ones(1,Third)];
Alloc_Sc2=Alloc_Sc(length(randperm(Alloc_Sc)));
it shows the error:
Error using randperm Size inputs must be scalar.
Stephen23
Stephen23 il 19 Mag 2016
@Hamid Reza Barzegar: Walter Roberson's answer clearly uses randperm(length(...)). You have written length(randperm(...).

Accedi per commentare.


Roger Stafford
Roger Stafford il 18 Mag 2016
Modificato: Roger Stafford il 18 Mag 2016
Let n be the desired length of the result and let a = [2 1 -1] :
p = randi(3,n,1); % <-- Corrected
v = a(p(randperm(n))); % v is your result % <-- Corrected
  5 Commenti
Roger Stafford
Roger Stafford il 18 Mag 2016
As I state above, your expression is in error in using "length(randperm(Alloc_Sc))" instead of "randperm(length(Alloc_Sc))".
Hamid Reza Barzegar
Hamid Reza Barzegar il 19 Mag 2016
Thanks for your reply i changed as you mentioned but the data is returned is number between 1 to 200 not my data now there is no error but not my data
first=100;
Second=50;
Third=50;
Alloc_Sc=[2*ones(1,first),ones(1,Second),-1*ones(1,Third)];
Alloc_Sc2=randperm(length(Alloc_Sc));

Accedi per commentare.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by