what is the problem with the second 'IF' loop ? Program terminates after entering into the loop.
2 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
kintali narendra
il 7 Giu 2016
Risposto: kintali narendra
il 8 Giu 2016
I am able to enter into the second "IF" but the simulink program terminates after executing the lines in the second "IF" condition. Simulink runs for the required time without the second "IF" condition.
function [Out] = LMAImplementation_Motor(In)
persistent eWithNoChange eWithDeltaL eWithDeltaK
e = In(1);
L = In(2);
K = In(3);
Clock = In(4);
if (0.0000 <= Clock) && (Clock <= 0.9999)
deltaK = 0; deltaL = 0;
eWithNoChange(end+1) = e;
[m,n] = size(eWithNoChange);
end
if n == 30001 %THIS LINE WAS BOLD
eWithNoChange(:,1) = [];
sizeofeWithNoChange = size(eWithNoChange)
end
if (1.0000 <= Clock) && (Clock <= 1.9999)
deltaL = L*0.1; deltaK = 0;
eWithDeltaL(end+1) = e;
end
Out = [deltaL,deltaK,Clock];
0 Commenti
Risposta accettata
Più risposte (0)
Vedere anche
Categorie
Scopri di più su Naming Conventions in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!