why always fopen fails?

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Aniya
Aniya il 22 Ott 2016
Risposto: Jan il 22 Ott 2016
in_file = fopen('name_of_file', 'wt');
It is my code i used to open a file .but it always return file identifier as -1.Why? Thank you for help.

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Jan
Jan il 22 Ott 2016
Most likely you do not have write permissions in the current folder. Use a folder with write permissions and absolute file names:
in_file = fopen(fullfile(tempdir, 'name_of_file'), 'wt');

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