How to Access to Fields of a Non-scalar Struct?

How can I create the 4-by-1 cell array D from the struct A?

A(1).B.C = 'a';
A(2).B.C = 'b';
A(3).B.C = 'c';
A(4).B.C = 'd';

D = 

      'a'
      'b'
      'c'
      'd'

Answer 1

[Walter Roberson]

D = arrayfun(@(IDX) A(IDX).B.C, (1:numel(A)).', 'Uniform', 0);

This is the safest approach, as it will work for the case where there are fields in addition to B within A, where some other approaches would not.

But in the specialized case where B is the only field inside A, then

temp = cell2mat(struct2cell(A));
D = {temp.C}.';

[Rightia Rollmann]

Thanks!

What does

.'

do for the code? I know ' operator, but I don't know .' operator.

[Walter Roberson]

.' is plain transpose. ' is conjugate transpose.

For arrays that are not numeric arrays, they come out the same, but I prefer to write .' to remove any ambiguity about whether I intend the transpose to be conjugate or not.