how use fftn and ifftn fourier transform

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xuan hau nguyen
xuan hau nguyen il 8 Giu 2017
Commentato: Adam il 8 Giu 2017
r=(fftn(matrix1) .* ifftn(matrix2)) ./ abs((fftn(matrix1) .* ifftn(matrix2))
r=ifftn(r)
then output is all of NaN in r matrix result, why happen this situation, how overcome this situation
thanks alot
  1 Commento
Adam
Adam il 8 Giu 2017
I have no idea what you are trying to do in that expression, but just break it down into the 4 components and then the expressions combining each and look at them in the debugger. You will soon find where your NaNs are.

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