Solve a system of equations
1 visualizzazione (ultimi 30 giorni)
Mostra commenti meno recenti
Rustem Devletov
il 10 Mag 2019
Modificato: Rustem Devletov
il 10 Mag 2019
Can anyone help me to write a code for solving the following system of equations?
w0=10; k1=3; k2=6; V1=20; V2=30;
x21=(w0+x13)/(w0+x13+k1*V1);
x22=(w0+x13);
x31=x22*x21/(x22+k2*V2);
x32=x22;
x13=x31*x32;
Suppose that x13 has an initial value (any number, let's say it is 1); Then we define what x21, x22, x31, 32 will be equal to and new value of x13*n;
If |x13*n-x|>=e (where e is a small number), then a new value of x13 should be x13*n, and we should solve that system until |x13*n-x13|<e;
Below is my idea, but I know it may be stupid but don't judge too harsh because I'm new to matlab and don't know how to do that.
w0=10; k1=3; k2=6; V1=20; V2=30; x13=1; e=0.00001; n=0.1
while abs(x13*n-x13)>=e
x21=(w0+x13)/(w0+x13+k1*V1);
x22=w0+x13;
x31=x22*x21/(x22+k2*V2);
x32=x22;
x13=x31*x32;
x13=x13*n;
end
It never stops counting
2 Commenti
Risposta accettata
Torsten
il 10 Mag 2019
x22 - w0 =
x13 =
x31 * x32 =
x22 * x21 / (x22+k2*V2) * x22 =
x22 * (x22/(x22+k1*V1)) / (x22+k2*V2) * x22
This gives a quadratic equation in x22. Solve it.
Once you have x22, x13 = x22 - w0.
8 Commenti
Torsten
il 10 Mag 2019
Then try your fsolve-code. fsolve uses Newton's (iterative) method. But it might converge to the wrong solution because the quadratic equation in x22 usually has two solutions.
Più risposte (0)
Vedere anche
Categorie
Scopri di più su Systems of Nonlinear Equations in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!