Get variable name into filename using strcat

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Louise Wilson
Louise Wilson on 26 Aug 2019
Commented: Walter Roberson on 27 Aug 2019
I am trying to create a filename for a .csv file using an existing variable name, which is a number e.g. '5100', and a manual input, e.g. 'files'.
My code:
x=sum(A(:,2:end),2); %column vector containing the sum of each row (from columns 2:end)
short_files=A(find(x==0),1); %get datenum corresponding to each row of zeros
formatOut='yymmddHHMMSS'; %convert datenum back to original filename format
short_files=datestr(short_files, formatOut);
filename_shortfiles=('short_files.csv'); %.csv filename
%try to get serial no into filename :-S
%filename_shortfiles=strcat(serialNo,'short_files.csv'); %.csv filename
Here, A is a matrix of data. Within that, I find the rows that contain zeros, and take the value in the first column of those particular rows. It is these values which I put in my output file that I am trying to write to a .csv file.
If I try
...this works, but I would like to have part of the filename change on each iteration of the loop, depending on the value of serialNo.
The value of serialNo changes on each iteration of an earlier part of my code...
serialNo is a 1x1 double, is this the problem? I tried converting it using char() but this didn't work.
Walter Roberson
Walter Roberson on 27 Aug 2019
The problem is in naming your variable "path" . Name your variable something else.
If you are trying to refer to the current directory, then you should use cd()

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Accepted Answer

Stephen on 26 Aug 2019
Nowhere do you describe/show what the output filename should look like, but this should get you started:
>> sno = 5100;
>> inp = 'short_files.csv';
>> [~,fnm,ext] = fileparts(inp);
>> out = sprintf('%s_%d%s',fnm,sno,ext)
out = short_files_5100.csv

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