How can i fix the error "Error using inline Input must be a character vector." and "Error in (line 9) g=inline(f);"

f=exp(2*exp(2)); %I tried this with other functions and it worked
a=0;
b=3;
n=30;
h=(b-a)/n; 
g=inline(f);
s=0;

for i=1:n
    s=h/2*(g(a+(i-1)*h)+g(a+(i)*h))+s
    
    mensaje=['En la iteracion ',num2str(i),', x es igual a ',num2str(s)];
    display(mensaje)
end

Answer 1

[Walter Roberson]

inline can only be used with character vectors.

Your f is a double precision scalar. If you were to format it into a character vector then would the resulting constant function be something that you would like to apply with an argument Ike you do?