- Launch it: >> cftool
- Select X data: X
- Select Y data: Y
- Select Z data Z
- Fir model type: Polynomial
- Degrees x: 2
- Degrees y: 2
- You will get the fit model
How to make a parabolic interpolation?
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Hello,
I have 3d graph as follow:
image1=imread('image.tif');
mu=[]
for i=1:30
for j=1:30
mu(i,j)=image1(i,j);
end
end
fmu=fft2(mu);
fmu(1,1)=0;
fmu2=fmu.*conj(fmu);
ps=ifft2(fmu2);
z=ps(1,1);
ps=real(fftshift(ps/z));
x=-15:1:14
y=-15:1:14
i=1:1:30
j=1:1:30
Z=ps(i,j)
[X,Y] = meshgrid(x,y);
surf(X,Y,Z)
set(gcf,'color','w') % pour les bordures.
xlabel('x (pixels)','FontSize',12, 'FontName','Times New Roman')
ylabel('y (pixels)', 'FontSize',12,'FontName','Times New Roman')
zlabel('Autocorrelation function', 'FontSize',12,'FontName','Times New Roman')
I want to make a prabolic interpolation in the vicinity of the maximum using the following equation :
Z=1-(a*x²+2b*x*y+c*y²)
How to make a parabolic interpolation? and how to get the parameters a, b and c?
Thank you for help.
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Risposte (2)
Sulaymon Eshkabilov
il 30 Ott 2019
Hi,
An easy solution is to employ the toolbox: cftool of MATLAB.
Good luck
1 Commento
John D'Errico
il 30 Ott 2019
Actually, no. Selecting 2nd degree for both x and y there will NOT yield the model the OP has asked to get.
Sulaymon Eshkabilov
il 30 Ott 2019
Modificato: Sulaymon Eshkabilov
il 30 Ott 2019
Hi,
An exact custom equation as asked in the question can be attained on step 5 Fit Model Type selection via Custom Equation (from drop down options) and manual entry of:
1 -( a*x^2 + 2*b*x*y+c*y^2)
Good luck.
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