Array indices must be positive integers or logical values.
Mostra commenti meno recenti
hFig = figure
clc;
v = 2.0;u = 2.0;
K = 8.617e-5;
trig = sin(4)*cos(4);
p = 2.7; t = 2.0; e = 1.6022e-19;
deltag = 0.0156; deltaxi = 0.0204;
n=[0.00 0.20 0.50 1.00];
T = linspace(0,700, 30); % However many you want.
delta1 = deltag./(K.*T); delta2 = deltaxi./(K.*T);
B0xi = besseli(0,delta2); B1xi = besseli(1, delta2);
B0g = besseli(0, delta1); B1g = besseli(1, delta1);
q = ((K^2).*T)./(e^2); g = p./(K.*T);
a = (B0g./B1g)- (2./delta1);
b = (1 - ((3./delta1).*(B0g./B1g)) + 6./(delta1.^2));
c = (1 - ((B1xi./B0xi).*(1./delta2)));
legendStrings = cell(length(n), 1);
for k1 = 1:length(n)
thisN = n(k1);
sigma = ((1i.*u-1-v.^2)./(v.^2-u.^2 +1-2i.*u)).*(1./(v.^2 +1));
sigmapri = thisN * ((1i.*u-1-v.^2)./((1+(thisN.*t)).^2 +v.^2).*(v.^2-u.^2 +1-2i.*u)).*(((B0g./B1g).*exp(0.9i.*pi))-(v./(v.^2 +1)));
w = sigma + sigmapri;
m = (w.*q.*trig((g.^2)-(2.*delta1.*g.*a)-(2.*delta2.*g.*(B1xi./B0xi))+((delta1.^2).*b)+(delta1.*delta2.*a.*(B1xi./B0xi))+((delta2.^2).*c)));
legendStrings{k1} = sprintf('n = %.2f', thisN);
plot(T, real(m), '.-', 'LineWidth', 2, 'MarkerSize', 15);
hold on;
drawnow;
end
grid on;
fontSize = 20;
xlabel('T(K)', 'FontSize', fontSize)
ylabel('\chi_\gamma', 'FontSize', fontSize)
title('\chi_\gamma vs. Temp(K)', 'FontSize', fontSize)
legend(legendStrings, 'Location', 'northeast');
% Maximize the figure window.
hFig.WindowState = 'maximized';
Risposta accettata
Più risposte (1)
Steven Lord
il 4 Apr 2020
m = (w.*q.*trig((g.^2)-(2.*delta1.*g.*a)-(2.*delta2.*g.*(B1xi./B0xi))+...
((delta1.^2).*b)+(delta1.*delta2.*a.*(B1xi./B0xi))+((delta2.^2).*c)));
You meant to multiply trig by the expression that follows it, not to use that expression to index into the (scalar) trig variable, right?
Categorie
Scopri di più su Structures in Centro assistenza e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!