Confusion with interp3 and interpn
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Hi,
According to my teacher, "for a matrix indexed as [M, N, P], the axis variables must be given in the order N, M, P" in relation to the swaping of variables at the interp3 line:
[X, Y, Z] = size(data);
ts= [20 30 20]
[x, y, z] = ndgrid((1:X)/X, (1:Y)/Y, (1:Z)/Z);
[x2, y2, z2] = ndgrid((1:ts(1))/(ts(1)), (1:ts(2))/(ts(2)), (1:ts(3))/(ts(3)));
test1= interp3(y, x, z, data, y2, x2, z2, 'linear');
However, I couldn't find this info on the function's page, nor it makes any sense to me (even though the computation seems correct!).
Any help welcome, thank you,
TS
5 Commenti
darova
il 24 Apr 2020
I don't understand the question. What are you asking?
Tahariet Sharon
il 26 Apr 2020
darova
il 25 Mag 2020
Did you try 'x,y,z' order? I think the result should be the same
Tahariet Sharon
il 25 Mag 2020
Modificato: Tahariet Sharon
il 25 Mag 2020
darova
il 25 Mag 2020
Maybe it's the answer on your question
Risposta accettata
Più risposte (1)
darova
il 25 Mag 2020
here is an example
[x,y] = meshgrid(1:5);
z = x.^2 + y.^2/2;
[x1,y1] = meshgrid(1:0.5:5);
z1 = interp2(x,y,z,x1,y1); % standart interpolation
z2 = interp2(y',x',z,y1',x1'); % interpolation y x
surf(x,y,z,'facecolor','none')
hold on
plot3(x1(:),y1(:),z1(:),'.r')
plot3(x1(:),y1(:),z2(:),'ob')
hold off
legend('original surface',...
'standard interpolation',...
'y x interpolation','location','north')
axis vis3d

2 Commenti
Tahariet Sharon
il 26 Mag 2020
Tahariet Sharon
il 26 Mag 2020
Modificato: Tahariet Sharon
il 26 Mag 2020
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