Getting a constant instead of (2*exp(-3/2))/3 + 1/3 solving a differential equation
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I want to get a constant number instead of (2*exp(-3/2))/3 + 1/3 solving a differential equation.
I have used dsolve() to find the solution;
Then,I have used sub() to substitute the parameter with a constant to get a number.
But I dont get any number.
Can anyone help with this?
1 Commento
John D'Errico
il 30 Mag 2020
That is a constant number. Just not in floating point form. If that is what you want, then use Star's suggestion. Either double or vpa will do it.
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