# I tried to solve problem but I couldn'!

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zehra ülgen il 18 Ott 2020
Commentato: zehra ülgen il 19 Ott 2020
Write a function called between that takes one scalar and two vectors of the same length as input arguments (the function does not have to check the format of the input) and returns one scalar output argument. If it is called like this, n = between(a,u,v), then n is equal to the number of indices ii for which the scalar a is between u(ii) and v(ii) or a is equal to u(ii) or v(ii). Here are some examples for the case in which the length of the vectors is 4:
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zehra ülgen il 18 Ott 2020
>> n = between(4,[5,0 -7 6], [3, 9, 4, 4])
n =
4
>> n = between(5,[5,0 -7 6], [3, 9, 4, 4])
n =
3
>> n = between(6,[5,0 -7 6], [3, 9, 4, 4])
n =
2
>> n = between(9,[5,0 -7 6], [3, 9, 4, 4])
n =
1
>> n = between(10,[5,0 -7 6], [3, 9, 4, 4])
n =
0

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### Risposta accettata

Payam Morsali il 18 Ott 2020
function y=compare(n,A,B)
y=0;
for i=1:length(A)
if n>=A(i) && n<=B(i)
y=y+1;
elseif n>=B(i) && n<=A(i)
y=y+1;
end
end
end
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zehra ülgen il 19 Ott 2020
I tried to solve problem.. That's my answer in a different way..
function n = betweenn(a, u, v)
n = sum((u <= a & a <= v) | (v <= a & a <= u));
end

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