comparing two matrix

A = 000010000000100070007000000013543570107013507135071213571357121357135713221223671323672322222223322222222223222232222222212222222223222222322222222222223222222132223222223672222236710123567223667213657223667223667213223213223213213650721076507657650076600725443444654344446544444444444635723671350070107013544444
a = 010000001070000070000135434507107234607232367236723232223232322232323232223222322222323222223222222332222222223222222223222223222212232222132212221323211355721365721365721365710135572136547254365071001355071000107100000000704
i need a method to use to compare this two matrix... like in pattern mining... i do not need it to find exactly the same match.... but more like 70% match, taking the sequence into little consideration

2 Commenti

Andrew Newell
Andrew Newell il 27 Apr 2011
That is a far from trivial problem, and there doesn't seem to be any MATLAB code for it. I recommend you do a search on "pattern mining algorithms" and then implement an algorithm in MATLAB.
Walter Roberson
Walter Roberson il 27 Apr 2011
Another term to look up is "fuzzy pattern matching".

Risposte (2)

Oyinda
Oyinda il 27 Apr 2011

0 voti

thanks for the hint the both of you (Andrew Newell, Walter Roberson) i decided to use Levenshtein distance
do
do il 6 Mag 2011

0 voti

Is there any comparation operator applied for matrixs, like the dot operator '.*', './', '.^' Hi, I have function f like this function z=f(x,y) if(x<1 & y <1) z=0; else z=1; end end And a script x=0:0.1:2; y=0:0.1:2; [X,Y]=meshgrid(x,y); Z=f(X,Y); mesh(X,Y,Z); When running this script, I got this errors: Z must be a matrix, not a scalar or vector.
It's because x and y here are two arrays, not scalar value. The script can run if I change the function f looks like this: function z = f( x,y ) for i=1:size(x,2) for j=1:size(y,2) if(x(i)<1 & y(j)<1) z(i,j)=0; else z(i,j)=1; end end end end
The broblem is that the new function runs much slower than the first one. I don't know if there is any comparation operator applied for arrays in this case, like the ".*" operator used in this function function z=f(x,y) z=x.*y; end Thank you very much.

1 Commento

Oleg Komarov
Oleg Komarov il 6 Mag 2011
ask your question in a separate thread: http://www.mathworks.com/matlabcentral/answers/6200-tutorial-how-to-ask-a-question-on-answers-and-get-a-fast-answer

Questa domanda è chiusa.

Richiesto:

il 27 Apr 2011

Chiuso:

il 20 Ago 2021

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by