Matrix addition hour values to day values

Hello guys it is my first question in here so you can imagine I'm not that good at matlab.

I got a table with 8760 lines (beta). Every value is an hour value and I wanted to sum every 24 lines to one day if you know what i mean.

So i need a loop or a possibility without "sum" command which can count 24 lines together and go to the next 24.

The results have to be a new matrix with 365 lines (so one year).

My code doesnt work but maybe you can help.

Its my first semester informatics and I've been trying to solve it for days.

            n = 1;
            N = 24;
            for i = b:c;
                for v = 1:8760
                    Beta(1,v) = beta(n,N);
                    n = n + 24
                    N = N + 24
                end
            end

Answer 1

[Cris LaPierre]

If I were going to do this, I would create a vector of datetimes incremented by 1 hour. I would then create a table with the datetimes and beta. I would then use groupsummary to calculate the sum of each day.

Here's a rough example.

beta = rand(8760,1);
d = datetime(2020,1,1,0,0,0)+hours(0:length(beta)-1)';
data = table(d,beta)

data = 8760x2 table
             d               beta  
    ____________________    _______

    01-Jan-2020 00:00:00    0.84722
    01-Jan-2020 01:00:00    0.19304
    01-Jan-2020 02:00:00    0.40865
    01-Jan-2020 03:00:00    0.88989
    01-Jan-2020 04:00:00    0.85154
    01-Jan-2020 05:00:00    0.53655
    01-Jan-2020 06:00:00    0.18732
    01-Jan-2020 07:00:00    0.60993
    01-Jan-2020 08:00:00    0.76008
    01-Jan-2020 09:00:00    0.21881
    01-Jan-2020 10:00:00    0.28571
    01-Jan-2020 11:00:00    0.85716
    01-Jan-2020 12:00:00    0.23839
    01-Jan-2020 13:00:00    0.85945
    01-Jan-2020 14:00:00    0.30243
    01-Jan-2020 15:00:00     0.2486

dailySum = groupsummary(data,'d','dayofyear','sum')

dailySum = 365x3 table
    dayofyear_d    GroupCount    sum_beta
    ___________    __________    ________

        1              24         10.841 
        2              24         11.897 
        3              24         14.002 
        4              24         11.924 
        5              24          12.63 
        6              24         12.117 
        7              24         10.108 
        8              24         12.824 
        9              24         12.373 
        10             24         12.469 
        11             24         11.382 
        12             24         13.871 
        13             24         10.718 
        14             24         13.249 
        15             24         12.944 
        16             24         14.145 

[Marek Dworak]

works perfectly, thank you !

Answer 2

[VBBV]

clc
clearvars
n = 1; 
beta = rand(8760,1);
x = 0;
v = 1;
F = zeros(365,1);
for k = 1:365
	while v <= 24*k
      x = x + beta(v,1);
	  v = v+1;	  
	end
	F(k) = x;	 
     x = 0;
end

Try this