Distribution graph velocity : how to make simple paraboloid of revolution?

4 visualizzazioni (ultimi 30 giorni)
Hello Guys,
I have a simple problem. You remember the mechanics of fluids? To calculate the velocity distribution in a circular tube (actual fluid) use the equation "u" and then to further develop the known Hagen-Poiseuille equation. If we consider the tube without inclination have this equation:
u = (-N 2 - R 2) / 4 * mi
if I assign values to 'r' and 'mi', we have a paraboloid of revolution that describes the velocity distribution of the fluid in the tube. How can I make this chart in matlab?
See the example:
a = [-50:50];
u = -((a.^2-(0.001^2))/(4*1.485));
plot(u,a)
or
syms x
ezplot(-((a^2-0.001^2)/(4*1.485)))
I put an fig in attach
Thank you in advance for all the help!

Risposta accettata

Youssef  Khmou
Youssef Khmou il 26 Mag 2013
Modificato: Youssef Khmou il 26 Mag 2013
hi,
i think your method works for this type of problems, try :
N=40; % Discretization
Vmax=20; % 20m/s
xc=0;
yc=0;
zc=0;
R=0.5; % radius of the tube
[x,y,z]=ellipsoid(xc,yc,zc,R,R,Vmax,N);
z(z<0)=0; % trick to truncate the unwanted elements
figure, surf(x,y,z), shading interp
xlabel('X axis (m)');
ylabel(' Y axis (m)');
zlabel(' Velocity (m/s)');
title(' Velocity profile');
  1 Commento
Artur M. G. Lourenço
Artur M. G. Lourenço il 27 Mag 2013
O/ Thank you so much! From here I think I can move forward only. Just leave it on the lack horinzontal and insert my data. Thank you again.

Accedi per commentare.

Più risposte (3)

Artur M. G. Lourenço
Artur M. G. Lourenço il 25 Mag 2013
sorry 'u' is:
u = (-a^2 - r^2) / 4 * mi

Youssef  Khmou
Youssef Khmou il 25 Mag 2013
hi here is an example before staring to answer the problem :
the veolcity is defined as :
V(r)= Vmax*(1-r²/R²), R is the radius of the tube :
R=.50 ; %radius in meters:
r=linspace(-R,R,30); % varying radius
Vmax=20 ; % suppose that the maximum velocity of fluid is 20 m/s
V=Vmax*(1-r.^2/R^2);
figure, bar(r,V);
figure, plot(V,r); xlabel(' Velocity'),ylabel(' varying radius')
  6 Commenti
Artur M. G. Lourenço
Artur M. G. Lourenço il 26 Mag 2013
almost! Missing only the base should be circular. I am trying here to change that!
Artur M. G. Lourenço
Artur M. G. Lourenço il 26 Mag 2013
see this, my graph looks like a half of cylinder
[x, y, z] = ellipsoid(0,0,0,5.9,3.25,3.25,30);
surfl(x, y, z)
colormap copper
axis equal

Accedi per commentare.


Artur M. G. Lourenço
Artur M. G. Lourenço il 26 Mag 2013
i can´t do it

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by