find the row and column value of a specific value in cell array

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i have a cell array with values
cellarr = {'a','b','c',3,5;'b',5,'a',[],[];'a','c',3,'a',4;'b','a','c','c',3};
i wanted to find the location where a particular number or string occurs
for example i want to get the location where the number = 3
so my expected output is
1st row 3rd column
3rd row 3rd column
4th row 5th column
[row,col] = find(___)
i want both the row and column position as it comes for find function
find not working with cell array
  3 Commenti
Elysi Cochin
Elysi Cochin il 13 Apr 2021
i tired that but not getting the row and column value
Xingwang Yong
Xingwang Yong il 13 Apr 2021
After using find(), you just need to convert the linear index into row and col index, see ind2sub

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Rik
Rik il 13 Apr 2021
You need to use a bit of trickery to use find (ismember will not work normally either).
cellarr = {...
'a','b','c', 3 ,5;...
'b', 5 ,'a',[] ,[];...
'a','c', 3 ,'a',4;...
'b','a','c','c',3};
val=3;
[row,col] = find(cellfun(@(x) isequal(val,x),cellarr));
[row,col]
ans = 3×2
3 3 1 4 4 5
  2 Commenti
Elysi Cochin
Elysi Cochin il 13 Apr 2021
Modificato: Elysi Cochin il 13 Apr 2021
is it possible to get in order?
row col
1 4
3 3
4 5
or sort based on row
Rik
Rik il 13 Apr 2021
This is the default order for find, but you can use sort (and its second output) to sort on row instead of column.

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