Euler's method code

2 visualizzazioni (ultimi 30 giorni)
Mike Asmanis
Mike Asmanis il 18 Giu 2021
Commentato: Mike Asmanis il 18 Giu 2021
Hello , how can I code this : y'(t)=cos(t + y) y(0)=0 t[0,3] (exact solution y(t)=-t + 2arctan(t)) using Euler's method like the code below?
clc
clear all
close all
h=0.01;
N=100; % number of steps
y(1)=1;
for n=1:N
y(n+1)=y(n)+h*(-6*y(n));
x(n+1)=n*h;
end
plot(x,y)
hold on
x=0:0.01:1;
y=exp(-6*x); % exact solution
plot(x,y)

Risposte (1)

Paul
Paul il 18 Giu 2021
The code that is posted solves a differential equation of the form
y'(x) = f(x,y), y(0) = y0
and compares it to the exact solution
y(x) = some function of x
over the interval
x [0 1]
As it happens, your problem has the exact same form, with the independent variable being t instead of x and the endpoint of the interval is different.
  2 Commenti
Mike Asmanis
Mike Asmanis il 18 Giu 2021
I know that it solves a different equation , i just need to solve my problem using a simillar or the exact code like the one i posted.
Mike Asmanis
Mike Asmanis il 18 Giu 2021
I'm getting Array indices must be positive integers or logical values.

Accedi per commentare.

Categorie

Scopri di più su Function Creation in Help Center e File Exchange

Prodotti

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by