Problem 1289. Evaluating continued fractions

Solution 207432

Submitted on 22 Feb 2013

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J.R.! Menzinger on 26 Feb 2013

not a bad idea but...
try this:

function ans = contfrac(c)
%%
c(:,1);
if size(c,2)>1
ans + 1./contfrac(c(:,2:end));
end

Test	Status	Code Input and Output
1	Fail	%% c=ones(1,40); x=(1+sqrt(5))/2; y=contfrac(c); assert(abs(y-x)<1e-15) Error: Index exceeds matrix dimensions.
2	Fail	%% c=[3 7 15 1 292 1 1 1 2 1 3 1 14]; x=pi; y=contfrac(c); assert(abs(y-x)<1e-15) Error: Index exceeds matrix dimensions.
3	Fail	%% c=[3 7 15 1]; x=355/113; y=contfrac(c); assert(abs(y-x)<1e-15) Error: Index exceeds matrix dimensions.
4	Fail	%% c=[1 1 1 3 1 5 1 7 1 9 1 11 1 13 1 15 1 17 1 19 1; 2 1 2 1 1 4 1 1 6 1 1 8 1 1 10 1 1 12 1 1 14]; x=[tan(1);exp(1)]; y=contfrac(c); assert(max(abs(y-x))<1e-15) Error: Attempted to access c(1); index out of bounds because numel(c)=0.
5	Fail	%% c=(1:9)'[1 2ones(1,20)]; x=sqrt([2;5;10;17;26;37;50;65;82]); y=contfrac(c); assert(max(abs(y-x))<1e-15) Error: Attempted to access c(1); index out of bounds because numel(c)=0.