might be best to add a test case to guard against test suite hacking
Far too few test cases. In fact, a serious issue with this problem is that there are too few parasitic numbers that will fit into even 64 bits for most values of n.
I've added some test cases, that will make it a bit more difficult to game this problem.
Cases 5 and 7 are identical, and I believe they are both wrong. 5 x 142857 = 714285. Isn't this a parasitic number? What am I missing?
Can the problem creator disqualify "solutions" that cheat? There should be a point penalty (-200) associated with cheating too.
There is 4, not 5
I mis-typed. 4 x 142857 = 571428, which is a shift right of 2. Incidentally, both n = 4 and 5 both make parasitic pairs with 142857.
Thus it is not a 4-parasitic number. It doesn't meet the definition. Nevertheless is a great example of a cyclic number. You can get different cyclic permutations when multiply 142857 by 1, 2, 3, 4, 5 and 6. For 5 you got shift by one digit, therefore it's 5-parasitic.
Ahhh, I see! Thanks, Jan - I get it now!
Not actually a general solution. Takes advantage of limited test cases.
Swap the first and last columns
How to find the position of an element in a vector without using the find function
give nth decimal place of pi
Replace multiples of 5 with NaN
07 - Common functions and indexing 1
All your base are belong to us
The Hitchhiker's Guide to MATLAB
Is my wife right?
Is my wife right? Now with even more wrong husband
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