Problem 1982. Battleship - Seaman Level

Created by Richard Zapor

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{"relationships":[{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/document","targetMode":"","relationshipId":"rId1","target":"/matlab/document.xml"},{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/output","targetMode":"","relationshipId":"rId2","target":"/matlab/output.xml"}],"parts":[{"partUri":"/matlab/document.xml","relationship":[],"contentType":"application/vnd.mathworks.matlab.code.document+xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n<w:document xmlns:w=\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\"><w:body><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:hyperlink w:docLocation=\"http://www.conceptispuzzles.com/index.aspx?uri=puzzle/battleships\"><w:r><w:t>Games Magazine Battleships</w:t></w:r></w:hyperlink><w:r><w:t> is a logic puzzle to find the Fleet given some map information and the number of Ship cells in every column and row. The fleet is made of a Battleship(4), two Cruisers(3), three Destroyers(2), and four Submarines(1). Thus the total filled cells is 20.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>The Seaman Level is the simplest and can be solved by direct evolution of current condition.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>Map information contains Water(0), Subs(1), Middle of a ship(6), Unknown(7), and the Aft(rear) of a ship. Ship going Up(2), Down(3), Left(4), and Right(5).</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>Ships have no diagonal or UDLR adjacency. The best way in Seaman to deal with Midship segments is to determine where it can not go to determine an orientation.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>The map is ringed by zeros to make m a 12x12 array.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:rPr><w:b/></w:rPr><w:t>Input:</w:t></w:r><w:r><w:t> m,r,c; m 12x12 of map values, r(12,1) of row sums, c(1,12) of col sums</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:rPr><w:b/></w:rPr><w:t>Output:</w:t></w:r><w:r><w:t> b; A binary 12x12 array</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:rPr><w:b/></w:rPr><w:t>Example:</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"code\"/></w:pPr><w:r><w:t><![CDATA[r=[0 2 0 2 2 2 3 2 3 0 4 0]';\nc=[0 4 0 3 1 3 1 4 0 1 3 0];\n\nm b\n000000000000 000000000000\n077757777770 000011000000\n077777777770 000000000000\n077777777770 000100010000\n077777777770 000100010000\n077777777770 010000010000\n077777777770 010000010010\n027777777760 010000000010\n077777777770 000101000010\n077777777770 000000000000\n077777477770 010001100100\n000000000000 000000000000]]></w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:rPr><w:b/></w:rPr><w:t>Future:</w:t></w:r><w:r><w:t> The example is a Level-4 Captain board. The future holds less explicit boards that will require recursion methods.</w:t></w:r></w:p></w:body></w:document>"},{"partUri":"/matlab/output.xml","contentType":"text/xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"no\" ?><embeddedOutputs><metaData><evaluationState>manual</evaluationState><layoutState>code</layoutState><outputStatus>ready</outputStatus></metaData><outputArray type=\"array\"/><regionArray type=\"array\"/></embeddedOutputs>"}]}

<a href = "http://www.conceptispuzzles.com/index.aspx?uri=puzzle/battleships">Games Magazine Battleships</a> is a logic puzzle to find the Fleet given some map information and the number of Ship cells in every column and row. The fleet is made of a Battleship(4), two Cruisers(3), three Destroyers(2), and four Submarines(1). Thus the total filled cells is 20.The Seaman Level is the simplest and can be solved by direct evolution of current condition.Map information contains Water(0), Subs(1), Middle of a ship(6), Unknown(7), and the Aft(rear) of a ship. Ship going Up(2), Down(3), Left(4), and Right(5).Ships have no diagonal or UDLR adjacency. The best way in Seaman to deal with Midship segments is to determine where it can not go to determine an orientation.The map is ringed by zeros to make m a 12x12 array.Input: m,r,c; m 12x12 of map values, r(12,1) of row sums, c(1,12) of col sumsOutput: b; A binary 12x12 arrayExample:<pre class="language-matlab">r=[0 2 0 2 2 2 3 2 3 0 4 0]';
c=[0 4 0 3 1 3 1 4 0 1 3 0];
</pre><pre class="language-matlab">m b
000000000000 000000000000
077757777770 000011000000
077777777770 000000000000
077777777770 000100010000
077777777770 000100010000
077777777770 010000010000
077777777770 010000010010
027777777760 010000000010
077777777770 000101000010
077777777770 000000000000
077777477770 010001100100
000000000000 000000000000
</pre>Future: The example is a Level-4 Captain board. The future holds less explicit boards that will require recursion methods.

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Problem 1982. Battleship - Seaman Level

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