Given the matrix A, return B in which all the rows that have one or more NaNs have been removed. So for
A = [ 1 5 8
-3 NaN 14
0 6 NaN ];then
B = [ 1 5 8 ]
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It's a good problem!
very good problem
ya.. but not so difficult though
nice trick with the " ' "))
very good problem
I really like this problem. It makes me to improve my solutions again and again. But it seems that I still use too many loops....
lol test case with transform was good one!
do not understand how one get so efficient solution on this (and to be honest other problems as well)
thanks you very much.
Why doesn't this work? It works when I use it on my computer...
function B = remove_nan_rows(A)
B = A;
B(any(isnan(A')),:) = [];
end
MATLABotic!
These types of problems are giving me so many useful functions
A(~sum(isnan(A),2),:) this workde for me
Cool!
Very good problem!
A easy problem if you know fuction isnan.
Nice one!
Oh
Easy one