Cody

Problem 2529. Solving Quadratic Equations (Version 2)

Solution 1917796

Submitted on 1 Sep 2019 by Quan Nguyen Dang
This solution is locked. To view this solution, you need to provide a solution of the same size or smaller.
Solve This Problem View on Solution Map

Test Suite

Test Status Code Input and Output
1   Pass
qe_correct1_1 = -1; qe_correct1_2 = -2; [qe_result1_1, qe_result1_2] = SolveQuadraticEquation(1, 3, 2); assert( (abs(qe_result1_1 - qe_correct1_1) < 0.0001 && ... abs(qe_result1_2 - qe_correct1_2) < 0.0001) || ... (abs(qe_result1_1 - qe_correct1_2) < 0.0001 && ... abs(qe_result1_2 - qe_correct1_1) < 0.0001) );

x1 = -1 x2 = -2
2   Pass
qe_correct2_1 = 0.224745; qe_correct2_2 = -2.22474; [qe_result2_1, qe_result2_2] = SolveQuadraticEquation(2, 4, -1); assert( (abs(qe_result2_1 - qe_correct2_1) < 0.0001 && ... abs(qe_result2_2 - qe_correct2_2) < 0.0001) || ... (abs(qe_result2_1 - qe_correct2_2) < 0.0001 && ... abs(qe_result2_2 - qe_correct2_1) < 0.0001) );

x1 = 0.2247 x2 = -2.2247
3   Pass
qe_correct3_1 = -1; qe_correct3_2 = -1; [qe_result3_1, qe_result3_2] = SolveQuadraticEquation(2, 4, 2); assert( (abs(qe_result3_1 - qe_correct3_1) < 0.0001 && ... abs(qe_result3_2 - qe_correct3_2) < 0.0001) || ... (abs(qe_result3_1 - qe_correct3_2) < 0.0001 && ... abs(qe_result3_2 - qe_correct3_1) < 0.0001) );

x1 = -1 x2 = -1
4   Pass
[qe_result4_1, qe_result4_2] = SolveQuadraticEquation(4, 4, 4); assert( isnan(qe_result4_1) && isnan(qe_result4_2) );

x1 = NaN x2 = NaN
5   Pass
[qe_result5_1, qe_result5_2] = SolveQuadraticEquation(9.1, 12, 4.1); assert( isnan(qe_result5_1) && isnan(qe_result5_2) );

x1 = NaN x2 = NaN

Suggested Problems

More from this Author6

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!