Consider the integer number sequence N (1 to infinity).

After each iteration, take out the (k+1)th elements; where k is the number of iteration.

you've to find the nth number in the remaining sequence after k-th iteration.

  • N= 1 2 3 4 5 6 7 8 9 10 11 12 ...
  • for k=1, N becomes --- 1, 3, 5, 7, 9, 11, 13, 15, 17, …
  • for k=2, N becomes --- 1, 3, 7, 9, 13, 15, 19, 21, 25, …
  • so for [k=2,n=8], output should be 21.
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George Berken goc3 Alexander Ross Lorenzo

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