Given a list of ordered pairs, and the order they should be placed in a line, find the sum of the absolute values of the differences.
list = [1 2
5 3
2 4
order = [1 3 2]
yields: [1 2][2 4][5 3]
or: abs(2-2) + abs(4-5)
or: 0 + 1
or: 1
Solution Stats
Problem Comments
3 Comments
Solution Comments
Show comments
Loading...
Problem Recent Solvers912
Suggested Problems
-
Given an unsigned integer x, find the largest y by rearranging the bits in x
2060 Solvers
-
1748 Solvers
-
Return the first and last characters of a character array
12349 Solvers
-
768 Solvers
-
String Array Basics, Part 1: Convert Cell Array to String Array; No Missing Values
2066 Solvers
More from this Author51
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Is Test #3 correct? When I solve it with pencil and paper, I get 15 instead of 14.
[5 4][1 2][2 4][7 5][4 8][4 5][1 6]
= -3 + 0 + 3 + -1 + -4 + -4
= 3+0+3+1+4+4
=15
Have I missed something?
No it's 14. With the ordering, you should get:
[5 4][1 2][2 4][4 8][1 6][4 5][7 5], and the sum is abs(4-1) + abs(2-2) + abs(4-4) + abs(8-1) + abs(6-4) + abs(5-7) = 3 + 0 + 0 + 7 + 2 + 2 = 14
good