Cody

# Problem 71. Read a column of numbers and interpolate missing data

Solution 2003098

Submitted on 5 Nov 2019 by SRUJANAV
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### Test Suite

Test Status Code Input and Output
1   Pass
s = { ... 'Day Temp' ' 1 1.3' ' 2 1.12' ' 3 17' ' 4 -32' ' 5 13' ' 6 4.4' ' 7 19'}; t_correct = [1.3 1.12 17 -32 13 4.4 19]; assert(isequal(read_and_interp(s),t_correct));

idx = 0×1 empty double column vector t33 = 1.3000 1.1200 17.0000 -32.0000 13.0000 4.4000 19.0000 t = 1.3000 1.1200 17.0000 -32.0000 13.0000 4.4000 19.0000

2   Pass
s = { ... 'Day Temp' ' 1 1.3' ' 2 1.12' ' 3 17' ' 4 16' ' 5 9999' ' 6 9999' ' 7 19'}; t_correct = [1.3 1.12 17 16 17 18 19]; assert(isequal(read_and_interp(s),t_correct));

idx = 5 6 y1 = 16 y2 = 19 x1 = 4 x2 = 7 sl = 1 c = 12 t3 = 7×1 cell array {'1.3' } {'1.12'} {'17' } {'16' } {'17' } {'9999'} {'19' } t3 = 7×1 cell array {'1.3' } {'1.12'} {'17' } {'16' } {'17' } {'18' } {'19' } t33 = 1.3000 1.1200 17.0000 16.0000 17.0000 18.0000 19.0000 t = 1.3000 1.1200 17.0000 16.0000 17.0000 18.0000 19.0000

3   Pass
s = { ... 'Day Temp' ' 1 -5' ' 2 19' ' 3 1' ' 4 9999' ' 5 3'}; t_correct = [-5 19 1 2 3]; assert(isequal(read_and_interp(s),t_correct));

idx = 4 y1 = 1 y2 = 3 x1 = 3 x2 = 5 sl = 1 c = -2 t3 = 5×1 cell array {'-5'} {'19'} {'1' } {'2' } {'3' } t33 = -5 19 1 2 3 t = -5 19 1 2 3