Cody

# Problem 80. Test for balanced parentheses

Solution 1453577

Submitted on 1 Mar 2018 by Russell
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### Test Suite

Test Status Code Input and Output
1   Pass
inStr = '()'; out_correct = true; assert(isequal(isBalanced(inStr),out_correct))

sign = 1 -1 foo = 1 0 out = logical 1

2   Pass
inStr = ')'; out_correct = false; assert(isequal(isBalanced(inStr),out_correct))

sign = -1 foo = -1 out = logical 0 out = logical 0

3   Pass
inStr = '(z*(a-(x+3))/(y))'; out_correct = true; assert(isequal(isBalanced(inStr),out_correct))

sign = 1 0 0 1 0 0 1 0 0 0 -1 -1 0 1 0 -1 -1 foo = 1 1 1 2 2 2 3 3 3 3 2 1 1 2 2 1 0 out = logical 1

4   Pass
inStr = ')('; out_correct = false; assert(isequal(isBalanced(inStr),out_correct))

sign = -1 1 foo = -1 0 out = logical 1 out = logical 0

5   Pass
inStr = '(x)(x-y)'; out_correct = true; assert(isequal(isBalanced(inStr),out_correct))

sign = 1 0 -1 1 0 0 0 -1 foo = 1 1 0 1 1 1 1 0 out = logical 1

6   Pass
inStr = ':-)'; out_correct = false; assert(isequal(isBalanced(inStr),out_correct))

sign = 0 0 -1 foo = 0 0 -1 out = logical 0 out = logical 0

7   Pass
inStr = ')()'; out_correct = false; assert(isequal(isBalanced(inStr),out_correct))

sign = -1 1 -1 foo = -1 0 -1 out = logical 0 out = logical 0

8   Pass
inStr = '(()'; out_correct = false; assert(isequal(isBalanced(inStr),out_correct))

sign = 1 1 -1 foo = 1 2 1 out = logical 0