Create n x 2n "mirror" matrix of this type:
For n = 2
m = [ 1 2 2 1
1 2 2 1 ]
For n = 3
m = [ 1 2 3 3 2 1
1 2 3 3 2 1
1 2 3 3 2 1 ]
This problem was fun. I was able to find a better way to solve beat my own solution. Not the best way though. But lot better.
Back to basics 3 - Temp Directory
Find perfect placement of non-rotating dominoes (easier)
intersection of matrices
subtract central cross
Who has power to do everything in this world?
Sum of series III
Sum of series IV
Sum of series I
Sum of series VI
Sum of series II
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